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Style numbers under name?
Old 04-10-2007, 02:46 PM   #1
Megamanny
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Default Style numbers under name?

always wanted to know but decided to ask now.

Right underneath the username there is a 1-12 that is like IIDX I would assume and a certain amount of numbers seem to be highlighted.

Can someone please explain to me what this does and how it is affected and such?

Thanks in advance.

P.S.: Mine is at 5 so far. I remember it used to be a lot less but I'm just curious.
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Old 04-11-2007, 02:01 PM   #2
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It has to do with how many posts you have. The more posts you have, the higher the number is.
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Old 06-08-2007, 07:15 AM   #3
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excuse me, i wanna ask. can you mention how much posts each level?
 

Old 06-08-2007, 01:07 PM   #4
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Quote:
Originally Posted by nejino_hito View Post
excuse me, i wanna ask. can you mention how much posts each level?
Well so far I've figured out that:

more than 50 posts = 1
more than 100 posts = 2
more than 200 posts = 3
more than 300 posts = 4
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Old 06-09-2007, 08:33 PM   #5
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Quote:
Originally Posted by koa5001 View Post
more than 50 posts = 1
more than 100 posts = 2
more than 200 posts = 3
more than 300 posts = 4
No, 400 posts = 4. At least from everyone I've seen and myself it's like that.

Also 800 = 5
1,500?? (not sure) = 6
and so on...
 

Old 06-12-2007, 09:34 AM   #6
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IIRC it's just level = 1+max(floor(log[2](1/50)),-1).

Or if this sounds complicated, it's described by the recursive relation:
(threshhold for level n+1) = 2*(threshhold for level n)
threshhold for level 1 = 50.

So for instance,

level(arka) = 1+max(floor(log[2](540/50)),-1) = 1+max(floor(log[2](10.8)),-1) = 1+max(floor(3.xyz),1) = 1 + 3 = 4

level(thoralf) = 1+max(floor(log[2](12/50)),-1) = 1 + -1 = 0

level(SulferDragon) = 1+max(floor(log[2](1013/50)),-1) = ...when the heck did YOU make so many posts?!
 

Old 06-12-2007, 09:55 AM   #7
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Quote:
Originally Posted by Arkaaito View Post
IIRC it's just level = 1+max(floor(log[2](1/50)),-1).

Or if this sounds complicated, it's described by the recursive relation:
(threshhold for level n+1) = 2*(threshhold for level n)
threshhold for level 1 = 50.

So for instance,

level(arka) = 1+max(floor(log[2](540/50)),-1) = 1+max(floor(log[2](10.8)),-1) = 1+max(floor(3.xyz),1) = 1 + 3 = 4

level(thoralf) = 1+max(floor(log[2](12/50)),-1) = 1 + -1 = 0

level(SulferDragon) = 1+max(floor(log[2](1013/50)),-1) = ...when the heck did YOU make so many posts?!
Haha, bro, I really don't understand all of that.
If there usually is an increase in posts really fast, the user might've bought a post count from the token shop that increases the surrent post count + 50.
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Old 06-12-2007, 11:02 AM   #8
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In English:

Again IIRC, the threshhold for level 1 is 50 posts. After that, the threshhold doubles for each successive level.

Spelled out: for level 2 it's 100 posts, level 3 it's 200 posts, level 4 it's 400 posts, level 5 it's 800 posts, level 6 it's 1600 posts, level 7 it's 3200 posts, level 8 it's 6400 posts, level 9 it's 12800 posts, level 10 it's 25600 posts, level 11 it's 51200 posts, and level 12 it's 102400 posts.

Why do we have so many levels?
 

Old 06-18-2007, 02:20 AM   #9
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Because IIDX does.
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Old 06-18-2007, 08:06 PM   #10
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Quote:
Originally Posted by Arkaaito View Post
IIRC it's just level = 1+max(floor(log[2](1/50)),-1).

Or if this sounds complicated, it's described by the recursive relation:
(threshhold for level n+1) = 2*(threshhold for level n)
threshhold for level 1 = 50.

So for instance,

level(arka) = 1+max(floor(log[2](540/50)),-1) = 1+max(floor(log[2](10.8)),-1) = 1+max(floor(3.xyz),1) = 1 + 3 = 4

level(thoralf) = 1+max(floor(log[2](12/50)),-1) = 1 + -1 = 0

level(SulferDragon) = 1+max(floor(log[2](1013/50)),-1) = ...when the heck did YOU make so many posts?!

tl;dr version: level 1 starts at 50 posts, and each successive level is double of the previous postcount.

I'm not sure if this is correct, for all I know, you may have to have 573,000 posts to get level 12. Moderators do not have access to that part of the backend of the site.
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Old 06-18-2007, 11:45 PM   #11
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I see... this helped me.
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